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#include "lib/chinese_remainder_theorem.hpp"
#ifndef CPLIB_LIB_CHINESE_REMAINDER_THEOREM_H_
#define CPLIB_LIB_CHINESE_REMAINDER_THEOREM_H_
#include <utility>
#include "../lib/extgcd.hpp"
// Chinese Remainder Theorem
// Find rem such that 0 <= rem < lcm(m1, m2) and
// rem % m1 = r1 and rem % m2 = r2
// Return { -1, -1 } if such rem doesn't exist,
// otherwise return { lcm(m1, m2), rem }
std::pair<long long, long long>
crt(long long m1, long long r1, long long m2, long long r2) {
long long x = 0, y = 0;
long long d = extgcd(m1, m2, x, y);
if (r1%d != r2%d) {
return { -1, -1 };
}
long long lcm = m1 / d * m2;
long long rem = ((r2 - r1) / d * x % (m2 / d)) * m1;
rem = ((rem + r1) % lcm + lcm) % lcm;
return { lcm, rem };
}
#endif // CPLIB_LIB_CHINESE_REMAINDER_THEOREM_H_
#line 1 "lib/chinese_remainder_theorem.hpp"
#include <utility>
#line 1 "lib/extgcd.hpp"
#include <tuple>
#line 6 "lib/extgcd.hpp"
// Find x and y such that a*x + b*y = gcd(a, b)
// Return gcd(a, b)
long long extgcd(long long a, long long b, long long &x, long long &y) {
if (b == 0) {
x = 1, y = 0;
return a;
}
long long ret = extgcd(b, a%b, x, y);
std::tie(x, y) = std::make_pair(y, x - a / b * y);
return ret;
}
#line 6 "lib/chinese_remainder_theorem.hpp"
// Chinese Remainder Theorem
// Find rem such that 0 <= rem < lcm(m1, m2) and
// rem % m1 = r1 and rem % m2 = r2
// Return { -1, -1 } if such rem doesn't exist,
// otherwise return { lcm(m1, m2), rem }
std::pair<long long, long long>
crt(long long m1, long long r1, long long m2, long long r2) {
long long x = 0, y = 0;
long long d = extgcd(m1, m2, x, y);
if (r1%d != r2%d) {
return { -1, -1 };
}
long long lcm = m1 / d * m2;
long long rem = ((r2 - r1) / d * x % (m2 / d)) * m1;
rem = ((rem + r1) % lcm + lcm) % lcm;
return { lcm, rem };
}